Saturday, 27 June 2020

Output of Series Heating Cable (Type-1)


How can be the output calculations for the series heating cable are done: 


Firstly we have some input:

V = Supply Voltage (V)

HL = Heat Loss (W/m)

TL = Total heating Cable Length (m)

𝛼 = Temperature Coefficient (1/◦C)

∆T = Temperature difference b/w maintain temperature and 20◦C


Now we find Ideal resistance (𝑅𝑖):- 


𝑅𝑖 = π‘‰2 / (𝐻𝐿 × π‘‡πΏ2) / (1 + 𝛼∆𝑇)


 Find out Unit 


𝑅𝑖 = π‘‰2/ ((π‘Š/π‘š) × π‘š2) / (1 + (1/◦ C) ×◦ C)

  

Unit of 𝑅𝑖 = (π‘‚β„Žπ‘š/π‘š) 


Now we will be select cable of less resistance from ideal resistance.


Now we will be calculating resistance on the maintain temperature (π‘…π‘š):-


π‘…π‘š = 𝑅𝑐 × (1 + Ξ±∆𝑇) 


𝑅𝑐 =  𝑆𝑒𝑙𝑒𝑐𝑑𝑒𝑑 π‘…π‘’π‘ π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘œπ‘“ πΆπ‘Žπ‘π‘™π‘’ (π‘‚β„Žπ‘š/π‘š) 


Ξ± =  Temperature Coefficient (1/◦ C)  


∆𝑇 =  Temperature difference b/w maintain temperature and 20 ◦ C  


Unit of π‘…π‘š = π‘‚β„Žπ‘š/π‘š


 Note:-  Ξ± value change as per heating cable resistance.


Now we will be calculating Output of heating cable:- 


𝑂𝑒𝑑𝑝𝑒𝑑 = π‘‰2 / π‘…π‘š / π‘‡πΏ2


 Find out Unit


𝑂𝑒𝑑𝑝𝑒𝑑 = π‘‰2 / (π‘‚β„Žπ‘š/π‘š) / π‘š2

 

Unit of 𝑂𝑒𝑑𝑝𝑒𝑑 = π‘Š/π‘š

 

 

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