How can be the output calculations for the series heating cable are done:
Firstly we have some input:
V = Supply Voltage (V)
HL = Heat Loss (W/m)
TL = Total heating Cable Length (m)
πΌ = Temperature Coefficient (1/◦C)
∆T = Temperature difference b/w maintain temperature and 20◦C
Now we find Ideal resistance (π π):-
π π = π2 / (π»πΏ × ππΏ2) / (1 + πΌ∆π)
Find out Unit
π π = π2/ ((π/π) × π2) / (1 + (1/◦ C) ×◦ C)
Unit of π π = (πβπ/π)
Now we will be select cable of less resistance from ideal resistance.
Now we will be calculating resistance on the maintain temperature (π π):-
π π = π π × (1 + Ξ±∆π)
π π = ππππππ‘ππ π ππ ππ π‘ππππ ππ πΆππππ (πβπ/π)
Ξ± = Temperature Coefficient (1/◦ C)
∆π = Temperature difference b/w maintain temperature and 20 ◦ C
Unit of π π = πβπ/π
Note:- Ξ± value change as per heating cable resistance.
Now we will be calculating Output of heating cable:-
ππ’π‘ππ’π‘ = π2 / π π / ππΏ2
Find out Unit
ππ’π‘ππ’π‘ = π2 / (πβπ/π) / π2
Unit of ππ’π‘ππ’π‘ = π/π
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