Output of Series Heating Cable (Type-2)
Here is how the output
calculations for the series heating cable are done:
V = Supply Voltage (V)
TL = Total heating Cable Length (m)
Rc = Cable Resistance (Ohm/m)
Now we find Current (I):-
I = V / (Rc X TL)
Unit of Current:-
I = V / (ohm / m X m)
I = V / ohm
I = A (Ampere)
Now we find Load (L):-
L = I X V
Unit of Load:-
L = A X V
L = W (Watt)
Now we find Heating Cable Output (O):-
O = L / TL
Unit of Heating Cable Output:-
O = W / m
O = Watt per meter.
Example:-
V = 230V
TL = 150m
Rc = 0.1, 0.2, 0.5 & 1Ohm/m
Heat Loss = 16W/m
I = 230 / (150 X 1) = 1.533A
L = 1.53 X 230 = 352.66W
O = 352.66 / 150 = 2.35 W/m
Result: - we don’t use this resistance cable
because there are not heat loss compensate by this cable, therefore we will try
for another cables.
I = 230 / (150 X .2) = 7.666A
L = 7.666 X 230 = 1763.33W
O = 1763.33 / 150 = 11.75 W/m
Result: - we used this cable for this length
because we put the 2 runs on the pipe therefore total output is 23.51W/m.
Note:-
2.
In this method α value is not matter
for calculation of output.
3.
Firstly will be decided exact total
heating cable length.
4.
Final output will be selected on the
base of heat loss.
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