Wednesday, 1 July 2020

Output of Series Heating Cable (Type-2)

 Output of Series Heating Cable (Type-2)

Here is how the output calculations for the series heating cable are done:

 Firstly we have some input:

V = Supply Voltage (V)

TL = Total heating Cable Length (m)

Rc = Cable Resistance (Ohm/m)

 

Now we find Current (I):-


I = V / (Rc X TL)


Unit of Current:-


I = V / (ohm / m X m)

I = V / ohm

I = A (Ampere)

 

Now we find Load (L):-


L = I X V


Unit of Load:-


L = A X V

L = W (Watt)

 

Now we find Heating Cable Output (O):-


O = L / TL


Unit of Heating Cable Output:-


O = W / m

O = Watt per meter.

 

Example:-

V = 230V

TL = 150m

Rc = 0.1, 0.2, 0.5 & 1Ohm/m

Heat Loss = 16W/m

I = 230 / (150 X 1) = 1.533A

L = 1.53 X 230 = 352.66W

O = 352.66 / 150 = 2.35 W/m

Result: - we don’t use this resistance cable because there are not heat loss compensate by this cable, therefore we will try for another cables.

I = 230 / (150 X .2) = 7.666A

L = 7.666 X 230 = 1763.33W

O = 1763.33 / 150 = 11.75 W/m

Result: - we used this cable for this length because we put the 2 runs on the pipe therefore total output is 23.51W/m.


Note:-

2.    In this method α value is not matter for calculation of output.

3.    Firstly will be decided exact total heating cable length.

4.    Final output will be selected on the base of heat loss.

 


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