Output of MI Heating Cable

 Output of MI Heating Cable

Here is how the output calculations for the MI heating cable are done:

 

Firstly we have some input:

V = Supply Voltage (V)

HL = Heat Loss (W/m)

TL = Total heating Cable Length (m)

 

Now we find Ideal resistance (Ri): -

Ri = (V X V) / (HL X TL X TL)

Unit of Ri: -

Ri = V2 / W / m X m X m

Ri = V2 / W X m

(V2 / W = Ohm)

Ri = Ohm/m

Now we will be select cable of less resistance from ideal resistance.

Now we will be calculating Output of heating cable (O):-

O = (V X V) / (Rc X TL X TL)

Where

Rc = Resistance of MI heating cable

Unit of Output: -

O = (V X V) / (ohm/m X m X m)

O = (V2) / (Ohm X m)

(V2 / Ohm = W)

O = W/m

 

Example: -

HL = 23.5 W/m

V = 230 V

TL = 26.3m

Output =?

Solution:-

Ri = (230 X 230) / (23.5 X 26.3 X 26.3)

Ri = 52900 / 16254.715

Ri = 3.2544 Ohm/m

Let now we assume we have some resistance like (5.6, 4.2, 2.3 & 1.6)

Then we select 2.3 ohm/m resistance cable therefore we calculated output: -

O = (230 X 230) / (2.3 X 26.3 X 26.3)

O = 52900 / 1590.887

O = 33.252 W/m