Monday, 29 June 2020

Output of Self-Regulating Heating Cable

Output of Self-Regulating Heating Cable


Output of Self-Regulating Heating Cable = (c + (m X Tm)) X Vo / Vs)


Where

c = Output of Heating Cable at 0◦C.

Vo = Voltage of Measuring Output.

Vs = Supply Voltage.

Tm = Maintain Temperature.

m = Output difference of per ◦C

 

m = (Os – Om) / (Ts – Tmm)


Where

Os = Output of Heating Cable Declared by Manufacturer’s at Standard Temperature.

Om = Output of Heating Cable Declared by Manufacturer’s at Maximum Maintain Temperature.

Ts = Manufacturer’s Declared output at Standard Temperature.

Tmm = Manufacturer’s Declared Maximum Maintain Temperature of Hating Cable

 

 

c = (Os (Ts X m))

Where

Os = Output of Heating Cable Declared by Manufacturer’s at Standard Temperature.

Ts = Manufacturer’s Declared output at Standard Temperature

m = Output difference of per ◦C


Example:-


A Manufacturer denoted the 5 W/ft @ 10◦C at 230 V. i.e.

5 W/ft = Output of Heating Cable per Feet

10◦C = Standard Temperature for 5 W/Ft Output.

230 V = Supply Voltage.

If 1 W/ft @ 150◦C at 230 V then Value of

m = (5 - 1) / (10 - 150)

   = 4 / (-140)

  = -0.0285

c = 5 – (10 X (-0.0285))

   = 5.28 W/ft @ 0◦C

If we calculate output at 30◦C for 230 V:-

 O = (5.28 + ((-0.0285) X 30)) X (230/230)

O = 5.28 + (-0.855) X 1

O = 4.425 W/ft


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