How to calculate voltage drop for power cable?
Solution:-
2. Three phase
Firstly we calculate on single phase supply:-
Vdp = (2 X Ic X (Rcos ᶿ + Xsinᶿ ) X L) / (1000 X Vs)
Where
Vdp = Voltage Drop (%)
Ic = Operating Current of
Circuit (A)
R = Power Cable Resistance
(Ohm/km)
Cos ᶿ = Power Factor
X = Conductor inductive
reactance (Ohm/km)
ᶿ = Phase angle of load
L = Power Cable Length (m)
Vs = Voltage Supply (V)
Here
Lo = Ic / Vs
Where
Lo = Load of Circuit (W)
Therefore
Vdp = (2 X L X (Rcos ᶿ + Xsinᶿ ) X L) / 1000XVs
Use 1000 for convert
ohm/km to ohm/m.
Power Factor Calculation:-
Cos ᶿ = Lo / (I X V)
Where
Lo = Load of Circuit (W)
I = Current (A)
V = voltage (V)
Let we assumed that
Cos ᶿ = Lo / (I X V) = 1
Xsinᶿ = Negligible
Therefore
Vdp = (2 X Lo X R X L) / 1000 X Vs
Now we calculate on Three phase supply:-
Vdp = (1.732 X Ic X (Rcos ᶿ + Xsinᶿ ) X L) / (1000 X Vs)
OR
After
consider assumptions then:-
Vdp = (1.732 X Ic X R X L) / (1000 X Vs)
OR
Vdp = (1.732 X Lo X R X L) / 1000 X Vs
Note: - used multiply by 100
for converting %.
Example:-1
Voltage Drop = ?
Operating Current of
Circuit = 24.05 A
Power Cable Resistance =
1.47 Ohm/km
Power Cable Length = 56
Voltage Supply = 240V
Solution:-
We know that 240V voltage for single phase, then we have formula:-
Vdp = (2 X Ic X R X L) / (1000 X Vs)
Now put the value:-
Vdp = (2 X 24.05 X 1.47 X 56) / (1000 X 240)
Vdp = 3959.592 / 240000
Vdp = 0.0164983
Vdp (%) = 0.0164983 X 100
Vdp (%) = 1.65
Example:-2
Voltage Drop = 1.25%
Operating Current of
Circuit = 22.26 A
Power Cable Resistance = ?
Power Cable Length = 72 m
Voltage Supply = 240V
Solution:-
We have equation for solution of calculate
voltage drop:-
Vdp = (2 X Ic X R X L) / (1000 X Vs)
Putting all value in this formula:-
(1.25 / 100) = (2 X 22.26 X R X 72) / (1000 X
240)
0.0125 = (3205.44 X R) / 240000
0.0125 X 240000 = (3205.44 X R)
3000 = 3205.44 X R
R = 3000 / 3205.44
R = 0.936 Ohm/m
Now we selected just less resistance cable.
And we have 0.93 Ohm/m cable resistance, so
we selected this cable.
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