
Skin
effect is a
phenomenon in alternating current (AC) systems where the current tends to flow
near the surface of a conductor, with the density of the current decreasing
exponentially with depth inside the conductor. This effect is important when
calculating heat tracing requirements because it affects the resistance of the
conductor and the amount of heat generated.
Steps to Calculate Heat Trace Power with Skin Effect Consideration
1. Understand the Parameters:
- Pipe diameter (D): Outer diameter of the
pipe.
- Power density (P): Heat generated per unit
length of the cable.
- Voltage (V): Voltage used in the
system.
- Conductor material: Usually copper or steel
for heating cables.
- Resistance (R): The resistance of the
wire will be impacted by the skin effect.
- Current frequency (f): AC frequency used
(typically 50 or 60 Hz).
- Insulation: Thermal insulation on the pipe and cable affects the heat dissipation and therefore the power needed.
2. Calculate the Resistance per Meter of Heat Trace Cable: The resistance (R) of the heat trace cable, considering the skin effect, can be calculated by:
R=ρ/A
Where:
- ρ = Resistivity of the
material (typically copper or aluminum).
- A = Cross-sectional area of the conductor, affected by skin depth.
3. Determine Skin Depth: The skin depth δ\deltaδ is the distance from the surface of the conductor where the current density falls to 1/e1/e1/e (approximately 37%) of its value at the surface. It is calculated as:
δ= squre root (ρ/πfμ)
Where:
- ρ = Resistivity of the
material.
- f = Frequency of the
current.
- μ = Permeability of the material (for copper, μ=4π×10−7 H/m)
4. Heat Generation: The heat generated in the cable due to resistance is given by Joule’s Law:
Q=I2R
Where:
- I = Current through the
conductor.
- R = Resistance of the conductor (including the effects of skin effect).
5. Power Calculation: The power required for the heat trace system can be calculated using:
P=V2R
Where:
- V = Voltage supplied to the
heat tracing cable.
- R = Resistance of the
cable, considering the skin effect.
Example Calculation
Let’s
assume the following parameters:
- Pipe diameter D=0.1m
- Heating cable is made of
copper (ρ=1.68×10−8 Ω⋅m).
- AC frequency f=60 Hz
- Voltage supplied V=120V
- Cable is designed to carry a
current of I=5A
Step 1: Calculate the skin depth
δ = square root (ρ/πfμ)
= square root (1.68×10−8)/(π×60×4π×10−7) ≈ 0.017 m
This
means that the current flows within 0.017 meters (1.7 cm) of the surface of the
conductor.
Step 2: Calculate resistance (simplified)
For
simplicity, let’s assume the cable’s cross-sectional area A is designed to
account for the skin effect. Let’s use a resistance R=0.5 Ω for the given
length.
Step 3: Heat Generation (Joule Heating)
Now,
using the current I=5A and resistance R=0.5 Ω:
Q = I2R
= 52×0.5 = 25×0.5 = 12.5 W
This is heat tracing cable output (W/m).
Step 4: Power Calculation
Given the
voltage V=120 V and resistance R=0.5 Ω:
P = V2R
= 1202x0.5 = 14400x0.5 = 28800W = 28.8kW
Thus, the
power required for the heat tracing system is 28.8kW.















