Calculating Maximum Power Cable length
We calculate maximum power cable length on single phase AC supply:-
Lmax = (1000 X V X VD) / (2 X I X (Rcos ᶿ + Xsinᶿ ))
Where
Lmax = Maximum
power cable length (m)
V = Maximum Permissible Voltage
Supply (V)
VD = Voltage drop (%)
I = Starting Current (A)
R = Power Cable Resistance
(Ω/m)
Cos ᶿ = Power Factor
X = Conductor inductive
reactance (Ω/m)
ᶿ = Phase angle of load (°)
We already learned how to calculate Power Cable Resistance in article Power Cable Size & Calculation of Voltage Drop.
Let
we assume:-
Power factor (Cos
ᶿ) = 1
Phase angle of load (ᶿ) =
90°
Lmax = (1000 X V X VD) / (2 X I X (R X 1 + Xsin90°))
We know that sin90° = 0, i.e.
Lmax = (1000 X V X VD) / (2 X I X (R + 0))
And we get final result-
Lmax = (1000 X V X VD) / (2 X I X R)
We calculate maximum power cable length on Three phase AC supply:-
Lmax = (1000 X V X VD) / (√3 X I X (Rcos ᶿ + Xsinᶿ))
Where
Lmax = Maximum
power cable length (m)
V = Maximum Permissible Voltage
Supply (V)
VD = Voltage drop (%)
I = Starting Current (A)
R = Power Cable Resistance
(Ω/km)
Cos ᶿ = Power Factor
X = Conductor inductive
reactance (Ω/km)
ᶿ = Phase angle of load (°)
Let
we assume:-
Power factor (Cos
ᶿ) = 1
Phase angle of load (ᶿ) =
90°
Same theory applicable here then we
get result:-
Lmax = (1000 X V X VD) / (√3 X I X R)
We calculate maximum power cable length on DC supply:-
Lmax = (1000 X Vdc X VD) / (2 X
I X R)
Lmax = Maximum
power cable length (m)
Vdc = Voltage
Supply (V)
VD = Voltage drop (%)
I = Starting Current (A)
R = Power Cable Resistance
(Ω/km)
Example1:-
V = 230V
I = 25A
R = 5.9
Cos ᶿ = 1
ᶿ = 90°
Phase = 1ph
VD = 5%
Lmax = ?
Solution:-
We use formula:-
Lmax = (1000 X V X VD) / (2 X I X R)
Putting all value in
formula:-
Lmax = (230 X
1000 X 5%) / (2 X 25 X 5.9)
Lmax = 11500 / 295
Lmax = 38.98m
We can use upto 38.98m of cable length in this parameter.
Example2:-
V = 440V
I = 120A
R = 0.495
Cos ᶿ = 1
ᶿ = 90°
Phase = 3ph
VD = 5%
Lmax = ?
Solution:-
We use formula:-
Lmax = (1000 X V X VD) / (√3 X I X R)
Putting all value in
formula:-
Lmax = (1000
X 440 X 5%) / (√3 X 120 X 0.495)
Lmax = 22000
/ 102.88
Lmax = 213.84m
We can use upto 213.84m of cable length in this parameter.